I ~Really~ Need some help here...

[Guren]

I know it isn't your responsibility to do the following, but without some help, I will fail this class and literally NOT graduate this year.

I am extremely bad at geometry and took it multiple times. As a senior, geometry is a Sophemore class and I am still in it. I really am stuck on this last assignment.

Please, from the bottom of my heart, I beg someone on this board to help a fellow FFXIonliner on my assignment.

Everyone I know already graduated while I had to stay longer then the rest of the seniors and complete this assignment.

Well, heres the problem.

-----

Scope of work:

Strip and sand current gym floor.
Paint shaded region with Navy Blue color
Stain white area with a natural maple stain
cover the entire gym with 3 coats of polyurethane gym coat finish.

Here is a picture of the diagram I received (I made this in paint in like 20 minutes:

http://img229.imageshack.us/img229/5307/mathcommontaskqs9.png

Number 1: Find the area of entire gym - That was easy, I got 4,743 ft

Number 2: Find the area that is going to be painted navy blue

Number 3: Find the area that is going to be painted natural maple stain

Number 4: The cost of a gallon of navy blue paint is $20.00. The label on the gallon of navy blue paint states that it will cover 400 square ft. How many gallons of blue paint will they have to buy to paint the court?

Number 5: The cost of natural maple stain is $30.00. The label says it will cover 400 square ft. How many gallons will they have to buy to paint the court?

Number 6: A 5 gallon pail of polyurethane (a glossy topcoat) costs $125.00 and will cover 400 square ft. If the ENTIRE court is to have 3 COATS of polyurethane, how many 5 gallon pails of polyurethane are needed to complete the job?

~~That is the entire project. I really have no one to help me and I am completely clueless in this area of school.

I am dead serious about the graduation thing. If I fail this class, I don't graduate.

Please, someone help, and thank you all that try and help.

~Guren

[Omni]

Re: I ~Really~ Need some help here...

I dont think you're thinking hard enough imo.

There's nothing tricky about this. It's just a lot of dividing and multiplying now since you found the area already.

[Guren]

Re: I ~Really~ Need some help here...

I dont think you're thinking hard enough imo.

There's nothing tricky about this. It's just a lot of dividing and multiplying now since you found the area already.

I really struggle with geometry though. I really just don't understand it. I have taken this class 3 times.

Also, I found the area because it is very simple. L*W so thats really easy.

I really do need help.

[Feba]

Re: I ~Really~ Need some help here...

This is pretty easy, and I suck at math.

The only tip you might even be close to needing is πr2. Beyond that, my advice would just be to break down the areas into easily manageable chunks. It's a pretty blocky diagram. Think of it as something a child made out of wooden blocks of two separate colors.

[Ellipses]

Re: I ~Really~ Need some help here...

There are only two kinds of shapes you're dealing with here. Rectangles and circles. With addition and subtraction, you should be able to find the length and width of every rectangle involved. You're given the radius of the circles, and your textbook should have the formula for the area of a circle. If it doesn't (Ho. Lee. Shit.), google does.

Once you know those areas, it isn't even geometry. It's just arithmetic.

You've got one big black rectangle you've already figured out. You have one small white rectangle, the measurements for which you can find with subtraction. You have areas to subtract from that rectangle.

[Kitalrez]

Re: I ~Really~ Need some help here...

First thing's first... calm down... have some tea or hot cocoa or something. Panicking just sets you up to make mistakes.

2. Ok, you're looking at this as too big of a project. Break it down into smaller parts that you already know. For this, let's carve off the two strips at the top and bottom and figure those out. 93 x 3 is 279 with two strips that gives you 558 ft^2. Next, take off 6 ft from both of the sides, (since you just withdrew the strips at the top and bottom, and there's no point painting twice). That leaves 45 x 6 for each of the side strips, you have two of those, making an area of the sides of 540 ft^2. Now, you haven't given me the length of the middle section on those 18 ft areas. I'll assume that this is a standard basketball court, however, and that the circle in the center is a true circle and the two half circles are the same width. Which means the radius of 6 for that half circle gives me a diameter of 12, (the width of both those rectangles). That means the rectangular painted portions are 12 x 18 x 2 or 432 ft^2. That just leaves you the two half circles and the single circle in the center. If these are the same size, then that leaves 2 x whatever the area of that circle in the center, or (pi x r^2). The radius we already know is 6, and 6 squared is 36.

Now, here's where I have to ask you a question. Because the answer to this question kind of hinges on how many decimal places your math class takes pi out to. Back in my HS days, we just did pi as 3.14. If you've got more places, you'll need to modify my answer.

3.14 x 36 x 2 = 226.08 ft^2 for the two circles. Now, add this to the rest and we get:

226.08 + 558 + 540 + 432 = 1756.08 ft^2.


3. This is just the answer above, subtracted from your total area. 4743 - 1756.08 = 2986.92 ft^2.

4. You need 1756.08 square feet of coverage, there's 400 square feet of coverage in a can of navy blue paint. Since you can't by part of a gallon of paint, you'll need to just go over this amount by less than one can. It's basically 5 cans.


5. Same deal with the maple. My calculator says you'll need 8 of those, rounding up.


6. Entire court, use the big area you found in the beginning. 12 of those.

[Saren]

Re: I ~Really~ Need some help here...

Some things that I think might help you.

1. Forget the questions for a minute and look at the diagram, see it just as a collection of shapes. Draw the diagram again on a new piece of paper for yourself; make sure it's a fresh one and make the diagram pretty big so you have room for labelling it.

2. Work out the length of every single straight line on your diagram, even if it’s obvious, write it on anyway. Don’t be afraid to draw extra lines if you need them or to section up a line into parts (useful for reminding yourself of the widths of borders)

3. Work out the area of all the easy shapes you can see (rectangles, circles, half circles) from your formulas and write them on your diagram. Don’t be afraid to split shapes up into smaller areas.

4. These sorts of problems tend to have one awkward shape that you can’t use a formula to find the area of. The way you find this area is by elimination as Kitalrez said. For example, to find the area of a piece of card with a circle cut out of it, find the area of the rectangle of the card (which is the area of the shape + the area of the circle), find the area of the circle then: area of the shape = area of rectangle – area of circle.

5. Once you have all the areas on your diagram then you can start worring about questions 2 and 3, identify which areas need to be blue and which areas need to be maple and find the totals.

6. When you do the paint questions remember that if you need a volume of paint that corresponds to 5.7 cans of paint that you can’t buy 0.7 of a can of paint, you have to buy in whole cans. i.e you can buy 5 cans of paint or 6 cans of paint and 5 cans wouldn’t give you enough.

7. General rule of thumb when you aren’t sure how many decimal places to use is to use 2.

[Omni]

Re: I ~Really~ Need some help here...

if no one said this already.... when they ask you how many cans of paint you will need, you will always need to round UP to the next whole number.

since you cant buy a partial can of paint.

[Feba]

Re: I ~Really~ Need some help here...

I think you guys might be being a bit too specific. The entire point of giving things like this as problems is to test a person's ability to work through them (because, really, if you can't learn how to practically apply math, there's little point in learning it at all). When you give him EVERY STEP, you might as well just reduce it to the problems for him.

[Guren]

Re: I ~Really~ Need some help here...

First thing's first... calm down... have some tea or hot cocoa or something. Panicking just sets you up to make mistakes.

2. Ok, you're looking at this as too big of a project. Break it down into smaller parts that you already know. For this, let's carve off the two strips at the top and bottom and figure those out. 93 x 3 is 279 with two strips that gives you 558 ft^2. Next, take off 6 ft from both of the sides, (since you just withdrew the strips at the top and bottom, and there's no point painting twice). That leaves 45 x 6 for each of the side strips, you have two of those, making an area of the sides of 540 ft^2. Now, you haven't given me the length of the middle section on those 18 ft areas. I'll assume that this is a standard basketball court, however, and that the circle in the center is a true circle and the two half circles are the same width. Which means the radius of 6 for that half circle gives me a diameter of 12, (the width of both those rectangles). That means the rectangular painted portions are 12 x 18 x 2 or 432 ft^2. That just leaves you the two half circles and the single circle in the center. If these are the same size, then that leaves 2 x whatever the area of that circle in the center, or (pi x r^2). The radius we already know is 6, and 6 squared is 36.

Now, here's where I have to ask you a question. Because the answer to this question kind of hinges on how many decimal places your math class takes pi out to. Back in my HS days, we just did pi as 3.14. If you've got more places, you'll need to modify my answer.

3.14 x 36 x 2 = 226.08 ft^2 for the two circles. Now, add this to the rest and we get:

226.08 + 558 + 540 + 432 = 1756.08 ft^2.


3. This is just the answer above, subtracted from your total area. 4743 - 1756.08 = 2986.92 ft^2.

4. You need 1756.08 square feet of coverage, there's 400 square feet of coverage in a can of navy blue paint. Since you can't by part of a gallon of paint, you'll need to just go over this amount by less than one can. It's basically 5 cans.


5. Same deal with the maple. My calculator says you'll need 8 of those, rounding up.


6. Entire court, use the big area you found in the beginning. 12 of those.

Thank you so much. You are my hero, especially since you posted how you got your answer as well (Which I need to show work)

I don't know how, but I will repay you someday, either on FFXI or when your in a jam.

~Guren

[Kitalrez]

Re: I ~Really~ Need some help here...

Fair enough. What's your blood type? I may need some organs/blood later on... Not sick ATM, but I suppose it can't hurt to nail this down in advance.

[Aeni]

Re: I ~Really~ Need some help here...

Fair enough. What's your blood type? I may need some organs/blood later on... Not sick ATM, but I suppose it can't hurt to nail this down in advance.

LOL funniest thing I've read online all day.